Roxy Paine’s sculpture “Defunct” (photo, Nicole Marti)
There were a couple of seminars today and one mentioned a result giving the following interesting corollary. Suppose we have a graph , and with each edge e we associate three numbers which we interpret in the following way: to construct edge e we need to use kilograms of aluminum, kilograms of beryllium, and kilograms of chromium. Later on we’ll decide to construct a spanning tree of the graph, which we would like to do cheaply; however the market price of the three metals affects which spanning tree is cheap. Nonetheless, it’s possible to fix a relatively small set of spanning trees ahead of time, and buy just one:
For k types of metals, there is a set S of spanning trees, so that for any assignment of prices to the metals, one of the spanning trees in S has minimal price among all spanning trees.
The theorem is interesting since the total number of spanning trees is exponential in . Is the theorem tight? I do not know.
The theorem follows from a more general result in the seminar (which was presented by Marco Di Summa, another member of my group at EPFL).
Take a polyhedron, and let D be the set of all directions of its edges. Then any projection of the polyhedron into k dimensions has at most vertices.
We combine this with the fact that the spanning tree polytope has at most directions (a similar fact holds for any matroid).
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